1.7 Warmup Solution
Problem
- Show the points (0, -4) and (3, 2) are on the graph of
.
- Find the x & y intercepts of the graph of the function

Solution
- To show the points lie on the graph we must evaluate the function at
the given x & y values.
To check the first point, we will let x = 0 and y = -4:
-4 = 2(0)-4
-4 = -4, so the point (0, -4) lies on the graph.
To check the second point, we will let x = 3 and y = 2
2 = 2(3)-4
2 = 2, so the point (3, 2) also lies on the graph.
- To find the x-intercept, we let y =0 and solve for x :
0 = 2x – 4
4 = 2x
2 = x
The x-intercept is (2, 0).
To find the y-intercept, we let x = 0 and solve for y:
y = 2(0)-4
y = -4
The y-intercept is (0, -4)
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